What is the general solution for 5sin(θ)=5 ?

The general solution for 5sin(θ)=5 is θ= pi/2+2pin

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5sin(θ)=5

5 sin (θ) = 5

θ = \frac{π}{2} + 2 πn

Degrees

θ = 9 0^{\circ} + 36 0^{\circ} n

Solution steps

5 sin (θ) = 5

Divide both sides by

5

5 sin (θ) = 5

Divide both sides by

5

\frac{5 sin ( θ )}{5} = \frac{5}{5}

Simplify

sin (θ) = 1

sin (θ) = 1

General solutions for

sin (θ) = 1

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

θ = \frac{π}{2} + 2 πn

θ = \frac{π}{2} + 2 πn

2 sin (3 x) = 2, 0 \leq x \leq 2 π

1 - tan (x) = 0

2 cos^{2} (x) - 3 cos (x) = 0, 0^{\circ} < x < 18 0^{\circ}

\frac{tan ( x )}{cos ( x )} = \frac{2}{3}

tan (x) + 2 cos (x) csc (x) = sec (x) cos (x) + cot (x)

What is the general solution for 5sin(θ)=5 ?
The general solution for 5sin(θ)=5 is θ= pi/2+2pin