What is the general solution for 2sin(3x)=2,0<= x<= 2pi ?

The general solution for 2sin(3x)=2,0<= x<= 2pi is x= pi/6 ,x=(5pi)/6 ,x=(3pi)/2

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2sin(3x)=2,0<= x<= 2pi

2 sin (3 x) = 2, 0 \leq x \leq 2 π

x = \frac{π}{6}, x = \frac{5 π}{6}, x = \frac{3 π}{2}

Solution steps

2 sin (3 x) = 2, 0 \leq x \leq 2 π

Divide both sides by

2

sin (3 x) = 1

General solutions for

sin (3 x) = 1

3 x = \frac{π}{2} + 2 πn

Solve

3 x = \frac{π}{2} + 2 πn : x = \frac{π}{6} + \frac{2 πn}{3}

x = \frac{π}{6} + \frac{2 πn}{3}

Solutions for the range

0 \leq x \leq 2 π

x = \frac{π}{6}, x = \frac{5 π}{6}, x = \frac{3 π}{2}

7.9615 = 59.2153 cos (x) - 12 sin (x)

1 - tan (x) = 0

2 cos^{2} (x) - 3 cos (x) = 0, 0^{\circ} < x < 18 0^{\circ}

\frac{tan ( x )}{cos ( x )} = \frac{2}{3}

tan (x) + 2 cos (x) csc (x) = sec (x) cos (x) + cot (x)

What is the general solution for 2sin(3x)=2,0<= x<= 2pi ?
The general solution for 2sin(3x)=2,0<= x<= 2pi is x= pi/6 ,x=(5pi)/6 ,x=(3pi)/2