What is the general solution for 0=4sin(2θ) ?

The general solution for 0=4sin(2θ) is θ=pin,θ= pi/2+pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

0=4sin(2θ)

0 = 4 sin (2 θ)

θ = πn, θ = \frac{π}{2} + πn

Solution steps

0 = 4 sin (2 θ)

Switch sides

4 sin (2 θ) = 0

Divide both sides by

4

sin (2 θ) = 0

General solutions for

sin (2 θ) = 0

2 θ = 0 + 2 πn, 2 θ = π + 2 πn

Solve

2 θ = 0 + 2 πn : θ = πn

Solve

2 θ = π + 2 πn : θ = \frac{π}{2} + πn

θ = πn, θ = \frac{π}{2} + πn

tan (θ) + 3 = 0

cos (2 x) - 4 cos (x) + 3 = 0

6 cos^{2} (A) - 5 cos (A) + 1 = 0

cos (x) tan^{2} (x) - 3 cos (x) = 0

2 sin (x) + 3 cot (x) - 3 csc (x) = 0

What is the general solution for 0=4sin(2θ) ?
The general solution for 0=4sin(2θ) is θ=pin,θ= pi/2+pin