What is the general solution for 5cos(x)-10sin(x)cos(x)=0,0<= x<= pi/2 ?

The general solution for 5cos(x)-10sin(x)cos(x)=0,0<= x<= pi/2 is x= pi/2 ,x= pi/6

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5cos(x)-10sin(x)cos(x)=0,0<= x<= pi/2

5 cos (x) - 10 sin (x) cos (x) = 0, 0 \leq x \leq \frac{π}{2}

x = \frac{π}{2}, x = \frac{π}{6}

Solution steps

5 cos (x) - 10 sin (x) cos (x) = 0, 0 \leq x \leq \frac{π}{2}

Factor

5 cos (x) - 10 sin (x) cos (x) : - 5 cos (x) (2 sin (x) - 1)

- 5 cos (x) (2 sin (x) - 1) = 0

Solving each part separately

cos (x) = 0 or 2 sin (x) - 1 = 0

cos (x) = 0, 0 \leq x \leq \frac{π}{2} : x = \frac{π}{2}

2 sin (x) - 1 = 0, 0 \leq x \leq \frac{π}{2} : x = \frac{π}{6}

Combine all the solutions

x = \frac{π}{2}, x = \frac{π}{6}

∣ (211) ∣ ∣ (- 37 - 1) ∣ (cos (x)) = 0

u, x = 4 sinh (u)

tan (x) = \frac{25}{32}

sin (x + 2 0^{\circ}) + sin (4 0^{\circ} - x) = 1

x, f = 2 cos (3 x^{2} - 1) e n t o n ces f

What is the general solution for 5cos(x)-10sin(x)cos(x)=0,0<= x<= pi/2 ?
The general solution for 5cos(x)-10sin(x)cos(x)=0,0<= x<= pi/2 is x= pi/2 ,x= pi/6