What is the general solution for cos(θ)=(11.14)/(13) ?

The general solution for cos(θ)=(11.14)/(13) is θ=0.54152…+2pin,θ=2pi-0.54152…+2pin

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cos(θ)=(11.14)/(13)

cos (θ) = \frac{11.14}{13}

θ = 0.54152 \dots + 2 πn, θ = 2 π - 0.54152 \dots + 2 πn

Solution steps

cos (θ) = \frac{11.14}{13}

Apply trig inverse properties

θ = arccos (\frac{11.14}{13}) + 2 πn, θ = 2 π - arccos (\frac{11.14}{13}) + 2 πn

Show solutions in decimal form

θ = 0.54152 \dots + 2 πn, θ = 2 π - 0.54152 \dots + 2 πn

cos (t) = 0.5

cos (2 θ) (4 sin^{2} (θ) + 1) = 0

sin (x) = 0.9906

sin (θ) = - 0.17

2 sin^{2} (x) - 1 = 0, - π \leq x \leq π

What is the general solution for cos(θ)=(11.14)/(13) ?
The general solution for cos(θ)=(11.14)/(13) is θ=0.54152…+2pin,θ=2pi-0.54152…+2pin