What is the general solution for sin(θ)=-0.17 ?

The general solution for sin(θ)=-0.17 is θ=-0.17082…+2pin,θ=pi+0.17082…+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sin(θ)=-0.17

sin (θ) = - 0.17

θ = - 0.17082 \dots + 2 πn, θ = π + 0.17082 \dots + 2 πn

Solution steps

sin (θ) = - 0.17

Apply trig inverse properties

θ = arcsin (- 0.17) + 2 πn, θ = π + arcsin (0.17) + 2 πn

Show solutions in decimal form

θ = - 0.17082 \dots + 2 πn, θ = π + 0.17082 \dots + 2 πn

2 sin^{2} (x) - 1 = 0, - π \leq x \leq π

sin (θ) = - 0.22

\frac{3}{2} sec (θ) + 3 cos (θ) = 3

2 sec (x) cos^{2} (x) = csc^{2} (x) - cot^{2} (x)

1 = 7 cos (\frac{π}{3} t)

What is the general solution for sin(θ)=-0.17 ?
The general solution for sin(θ)=-0.17 is θ=-0.17082…+2pin,θ=pi+0.17082…+2pin