What is the general solution for -sqrt(3)+3=2sqrt(6)cos(θ) ?

The general solution for -sqrt(3)+3=2sqrt(6)cos(θ) is θ=1.30899…+2pin,θ=2pi-1.30899…+2pin

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-sqrt(3)+3=2sqrt(6)cos(θ)

- 3 + 3 = 26 cos (θ)

θ = 1.30899 \dots + 2 πn, θ = 2 π - 1.30899 \dots + 2 πn

Solution steps

- 3 + 3 = 26 cos (θ)

Switch sides

26 cos (θ) = - 3 + 3

Divide both sides by

26

cos (θ) = \frac{2 ( - 1 + 3 )}{4}

Apply trig inverse properties

θ = arccos (\frac{2 ( - 1 + 3 )}{4}) + 2 πn, θ = 2 π - arccos (\frac{2 ( - 1 + 3 )}{4}) + 2 πn

Show solutions in decimal form

θ = 1.30899 \dots + 2 πn, θ = 2 π - 1.30899 \dots + 2 πn

sin (\frac{π}{2} - x) = - 1, 0^{\circ} \leq x \leq 36 0^{\circ}

2 sin (5 x) = - 1

4 sin^{2} (x) + 8 cos (x) - 7 = 0

6 (cos (b))^{2} + cos (b) - 1 = 0

sin (θ) = \frac{1.33}{2.42}

What is the general solution for -sqrt(3)+3=2sqrt(6)cos(θ) ?
The general solution for -sqrt(3)+3=2sqrt(6)cos(θ) is θ=1.30899…+2pin,θ=2pi-1.30899…+2pin