What is the general solution for 4sin(x)+sqrt(2)=2sin(x) ?

The general solution for 4sin(x)+sqrt(2)=2sin(x) is x=(5pi)/4+2pin,x=(7pi)/4+2pin

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4sin(x)+sqrt(2)=2sin(x)

4 sin (x) + 2 = 2 sin (x)

x = \frac{5 π}{4} + 2 πn, x = \frac{7 π}{4} + 2 πn

Solution steps

4 sin (x) + 2 = 2 sin (x)

Solve by substitution

sin (x) = - \frac{2}{2}

sin (x) = - \frac{2}{2} : x = \frac{5 π}{4} + 2 πn, x = \frac{7 π}{4} + 2 πn

Combine all the solutions

x = \frac{5 π}{4} + 2 πn, x = \frac{7 π}{4} + 2 πn

y, - \frac{1}{2} cot (y) = \frac{t ^{2}}{2} + C

4 cos (2 t) + 1 = 3, 0, \frac{π}{2}

A, cos (\frac{π}{3} - A) = 2 sin (A)

- 3 + 3 = 26 cos (θ)

sin (\frac{π}{2} - x) = - 1, 0^{\circ} \leq x \leq 36 0^{\circ}

What is the general solution for 4sin(x)+sqrt(2)=2sin(x) ?
The general solution for 4sin(x)+sqrt(2)=2sin(x) is x=(5pi)/4+2pin,x=(7pi)/4+2pin