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Popular >

(sin(2x)+1)=0,0<= x<360

Solution

(sin (2 x) + 1) = 0, 0^{\circ} \leq x < 36 0^{\circ}

Solution

x = 13 5^{\circ}, x = 31 5^{\circ}

+1

Solution steps

(sin (2 x) + 1) = 0, 0^{\circ} \leq x < 36 0^{\circ}

Move

1

to the right side

sin (2 x) = - 1

General solutions for

sin (2 x) = - 1

2 x = 27 0^{\circ} + 36 0^{\circ} n

Solve

2 x = 27 0^{\circ} + 36 0^{\circ} n : x = 13 5^{\circ} + 18 0^{\circ} n

x = 13 5^{\circ} + 18 0^{\circ} n

Solutions for the range

0 \leq x < 36 0^{\circ}

x = 13 5^{\circ}, x = 31 5^{\circ}

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Frequently Asked Questions (FAQ)

What is the general solution for (sin(2x)+1)=0,0<= x<360 ?
The general solution for (sin(2x)+1)=0,0<= x<360 is x=135,x=315