What is the general solution for 2sin^2(u)=1+,u ?

The general solution for 2sin^2(u)=1+,u is No Solution for u\in\mathbb{R}

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2sin^2(u)=1+,u

2 sin^{2} (u) = 1 +, u

No Solution for u \in R

Solution steps

2 sin^{2} (u) = 1 +, u

Solve by substitution

sin (u) = \frac{1}{2}, sin (u) = - \frac{1}{2}

sin (u) = \frac{1}{2}, u :

No Solution

sin (u) = - \frac{1}{2}, u :

No Solution

Combine all the solutions

No Solution for u \in R

8.5 = 12 sin (a)

cos (x) = \frac{1}{15}

cot (θ) = - 3, 0 \leq θ < 2 π

\frac{sin ( 9 0 ^{\circ} )}{458.912} = \frac{sin ( x )}{450}

0 = \frac{2 π ^{2} cos ( \frac{π x}{10} )}{25}

What is the general solution for 2sin^2(u)=1+,u ?
The general solution for 2sin^2(u)=1+,u is No Solution for u\in\mathbb{R}