What is the general solution for tan(25)=cot(2x+5) ?

The general solution for tan(25)=cot(2x+5) is x=-5/2+32.5+(180n)/2

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tan(25)=cot(2x+5)

tan (2 5^{\circ}) = cot (2 x + 5)

x = - \frac{5}{2} + 32. 5^{\circ} + \frac{18 0 ^{\circ} n}{2}

Solution steps

tan (2 5^{\circ}) = cot (2 x + 5)

Switch sides

cot (2 x + 5) = tan (2 5^{\circ})

Apply trig inverse properties

2 x + 5 = arccot (tan (2 5^{\circ})) + 18 0^{\circ} n

Solve

2 x + 5 = arccot (tan (2 5^{\circ})) + 18 0^{\circ} n : x = - \frac{5}{2} + 32. 5^{\circ} + \frac{18 0 ^{\circ} n}{2}

x = - \frac{5}{2} + 32. 5^{\circ} + \frac{18 0 ^{\circ} n}{2}

sin (a) = 0.4

sin (a) = 0.2

sin (2 x) = 1.47 (sin (x))^{2}

2 sin^{2} (u) = 1 +, u

8.5 = 12 sin (a)

What is the general solution for tan(25)=cot(2x+5) ?
The general solution for tan(25)=cot(2x+5) is x=-5/2+32.5+(180n)/2