What is the general solution for -8cos(θ)=4sqrt(3) ?

The general solution for -8cos(θ)=4sqrt(3) is θ=(5pi)/6+2pin,θ=(7pi)/6+2pin

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-8cos(θ)=4sqrt(3)

- 8 cos (θ) = 43

θ = \frac{5 π}{6} + 2 πn, θ = \frac{7 π}{6} + 2 πn

Solution steps

- 8 cos (θ) = 43

Divide both sides by

- 8

cos (θ) = - \frac{3}{2}

General solutions for

cos (θ) = - \frac{3}{2}

θ = \frac{5 π}{6} + 2 πn, θ = \frac{7 π}{6} + 2 πn

2 sin (3 a) = - 1

sin (b) = 12 (\frac{sin ( 4 2 ^{\circ} )}{22})

arctan (\frac{3}{1}) = tan (θ)

2 sin^{2} (x) - 5 cos (x) + 5 = 0

tan (x) = \frac{20}{40}

What is the general solution for -8cos(θ)=4sqrt(3) ?
The general solution for -8cos(θ)=4sqrt(3) is θ=(5pi)/6+2pin,θ=(7pi)/6+2pin