What is the general solution for 2sin(3a)=-1 ?

The general solution for 2sin(3a)=-1 is a=(7pi}{18}+(2pin)/3 ,a=(11pi)/(18)+\frac{2pin)/3

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2sin(3a)=-1

2 sin (3 a) = - 1

a = \frac{7 π}{18} + \frac{2 πn}{3}, a = \frac{11 π}{18} + \frac{2 πn}{3}

Solution steps

2 sin (3 a) = - 1

Divide both sides by

2

sin (3 a) = - \frac{1}{2}

General solutions for

sin (3 a) = - \frac{1}{2}

3 a = \frac{7 π}{6} + 2 πn, 3 a = \frac{11 π}{6} + 2 πn

Solve

3 a = \frac{7 π}{6} + 2 πn : a = \frac{7 π}{18} + \frac{2 πn}{3}

Solve

3 a = \frac{11 π}{6} + 2 πn : a = \frac{11 π}{18} + \frac{2 πn}{3}

a = \frac{7 π}{18} + \frac{2 πn}{3}, a = \frac{11 π}{18} + \frac{2 πn}{3}

sin (b) = 12 (\frac{sin ( 4 2 ^{\circ} )}{22})

arctan (\frac{3}{1}) = tan (θ)

2 sin^{2} (x) - 5 cos (x) + 5 = 0

tan (x) = \frac{20}{40}

2 sin (x + \frac{π}{4}) = 0

What is the general solution for 2sin(3a)=-1 ?
The general solution for 2sin(3a)=-1 is a=(7pi}{18}+(2pin)/3 ,a=(11pi)/(18)+\frac{2pin)/3