What is the general solution for 2sin^2(x)-5cos(x)+5=0 ?

The general solution for 2sin^2(x)-5cos(x)+5=0 is x=2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2sin^2(x)-5cos(x)+5=0

2 sin^{2} (x) - 5 cos (x) + 5 = 0

x = 2 πn

Solution steps

2 sin^{2} (x) - 5 cos (x) + 5 = 0

Rewrite using trig identities

7 - 2 cos^{2} (x) - 5 cos (x) = 0

Solve by substitution

cos (x) = - \frac{7}{2}, cos (x) = 1

cos (x) = - \frac{7}{2} :

No Solution

cos (x) = 1 : x = 2 πn

Combine all the solutions

x = 2 πn

tan (x) = \frac{20}{40}

2 sin (x + \frac{π}{4}) = 0

sin (x) = \frac{2 ( 5.5 \cdot 1 0 ^{- 7} )}{3.36 \cdot 1 0 ^{- 5}}

sin (x - 3 0^{\circ}) = cos (1 5^{\circ})

tan (x) = 2.8867

What is the general solution for 2sin^2(x)-5cos(x)+5=0 ?
The general solution for 2sin^2(x)-5cos(x)+5=0 is x=2pin