pt

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular Trigonometria >

cos(xpi)=(-1)^n

Solução

cos (x π) = (- 1)^{n}

Solução

x = \frac{arccos ( ( - 1 ) ^{n} )}{π} + 2 k, x = - \frac{arccos ( ( - 1 ) ^{n} )}{π} + 2 k

Passos da solução

cos (x π) = (- 1)^{n}

Aplique as propriedades trigonométricas inversas

cos (x π) = (- 1)^{n}

Soluções gerais para

cos (x π) = (- 1)^{n}

cos (x) = a \Rightarrow x = arccos (a) + 2 πk, x = - arccos (a) + 2 πk

x π = arccos ((- 1)^{n}) + 2 πk, x π = - arccos ((- 1)^{n}) + 2 πk

x π = arccos ((- 1)^{n}) + 2 πk, x π = - arccos ((- 1)^{n}) + 2 πk

Resolver

x π = arccos ((- 1)^{n}) + 2 πk : x = \frac{arccos ( ( - 1 ) ^{n} )}{π} + 2 k

x π = arccos ((- 1)^{n}) + 2 πk

Dividir ambos os lados por

π

x π = arccos ((- 1)^{n}) + 2 πk

Dividir ambos os lados por

π

\frac{x π}{π} = \frac{arccos ( ( - 1 ) ^{n} )}{π} + \frac{2 πk}{π}

Simplificar

x = \frac{arccos ( ( - 1 ) ^{n} )}{π} + 2 k

x = \frac{arccos ( ( - 1 ) ^{n} )}{π} + 2 k

Resolver

x π = - arccos ((- 1)^{n}) + 2 πk : x = - \frac{arccos ( ( - 1 ) ^{n} )}{π} + 2 k

x π = - arccos ((- 1)^{n}) + 2 πk

Dividir ambos os lados por

π

x π = - arccos ((- 1)^{n}) + 2 πk

Dividir ambos os lados por

π

\frac{x π}{π} = - \frac{arccos ( ( - 1 ) ^{n} )}{π} + \frac{2 πk}{π}

Simplificar

x = - \frac{arccos ( ( - 1 ) ^{n} )}{π} + 2 k

x = - \frac{arccos ( ( - 1 ) ^{n} )}{π} + 2 k

x = \frac{arccos ( ( - 1 ) ^{n} )}{π} + 2 k, x = - \frac{arccos ( ( - 1 ) ^{n} )}{π} + 2 k

Gráfico

Exemplos populares

3 csc (θ) = 4.5

cos^3(x)= 1/(4(3cos(x)+cos(3x)))

cos^{3} (x) = \frac{1}{4 ( 3 cos ( x ) + cos ( 3 x ) )}

solvefor w,s(t)=Ae^{-ct}cos(wt+θ)

so l v e f or w, s (t) = A e^{- c t} cos (wt + θ)

sqrt(2)=2sin(x)

2 = 2 sin (x)

6 sin (\frac{π}{4} x) = 3