What is the general solution for cos(xpi)=(-1)^n ?

The general solution for cos(xpi)=(-1)^n is x=(arccos((-1)^n))/pi+2k,x=-(arccos((-1)^n))/pi+2k

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cos(xpi)=(-1)^n

cos (x π) = (- 1)^{n}

x = \frac{arccos ( ( - 1 ) ^{n} )}{π} + 2 k, x = - \frac{arccos ( ( - 1 ) ^{n} )}{π} + 2 k

Solution steps

cos (x π) = (- 1)^{n}

Apply trig inverse properties

x π = arccos ((- 1)^{n}) + 2 πk, x π = - arccos ((- 1)^{n}) + 2 πk

Solve

x π = arccos ((- 1)^{n}) + 2 πk : x = \frac{arccos ( ( - 1 ) ^{n} )}{π} + 2 k

Solve

x π = - arccos ((- 1)^{n}) + 2 πk : x = - \frac{arccos ( ( - 1 ) ^{n} )}{π} + 2 k

x = \frac{arccos ( ( - 1 ) ^{n} )}{π} + 2 k, x = - \frac{arccos ( ( - 1 ) ^{n} )}{π} + 2 k

3 csc (θ) = 4.5

cos^{3} (x) = \frac{1}{4 ( 3 cos ( x ) + cos ( 3 x ) )}

w, s (t) = A e^{- c t} cos (wt + θ)

2 = 2 sin (x)

6 sin (\frac{π}{4} x) = 3

What is the general solution for cos(xpi)=(-1)^n ?
The general solution for cos(xpi)=(-1)^n is x=(arccos((-1)^n))/pi+2k,x=-(arccos((-1)^n))/pi+2k