What is the general solution for (2sec^2(x)-1)/(sec^2(x))=sec^2(x) ?

The general solution for (2sec^2(x)-1)/(sec^2(x))=sec^2(x) is x=2pin,x=pi+2pin

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(2sec^2(x)-1)/(sec^2(x))=sec^2(x)

\frac{2 sec ^{2} ( x ) - 1}{sec ^{2} ( x )} = sec^{2} (x)

x = 2 πn, x = π + 2 πn

Solution steps

\frac{2 sec ^{2} ( x ) - 1}{sec ^{2} ( x )} = sec^{2} (x)

Solve by substitution

sec (x) = 1, sec (x) = - 1

sec (x) = 1 : x = 2 πn

sec (x) = - 1 : x = π + 2 πn

Combine all the solutions

x = 2 πn, x = π + 2 πn

9 (sin (x) - 0.6 π) + 8 = 0

t, v = 100 cos (50 t + 2 0^{\circ}) v

cos (2 x) = sin (\frac{π}{2} - x)

sin (x) = sin (5 0^{\circ})

n, y = - sin (2 (\frac{3 π}{4} + πn)) 2

What is the general solution for (2sec^2(x)-1)/(sec^2(x))=sec^2(x) ?
The general solution for (2sec^2(x)-1)/(sec^2(x))=sec^2(x) is x=2pin,x=pi+2pin