What is the general solution for 9(sin(x)-0.6pi)+8=0 ?

The general solution for 9(sin(x)-0.6pi)+8=0 is x=1.48207…+2pin,x=pi-1.48207…+2pin

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9(sin(x)-0.6pi)+8=0

9 (sin (x) - 0.6 π) + 8 = 0

x = 1.48207 \dots + 2 πn, x = π - 1.48207 \dots + 2 πn

Solution steps

9 (sin (x) - 0.6 π) + 8 = 0

Move

8

to the right side

9 (sin (x) - 0.6 π) = - 8

Divide both sides by

9

sin (x) - 1.88495 \dots = - \frac{8}{9}

Move

1.88495 \dots

to the right side

sin (x) = 0.99606 \dots

Apply trig inverse properties

x = arcsin (0.99606 \dots) + 2 πn, x = π - arcsin (0.99606 \dots) + 2 πn

Show solutions in decimal form

x = 1.48207 \dots + 2 πn, x = π - 1.48207 \dots + 2 πn

t, v = 100 cos (50 t + 2 0^{\circ}) v

cos (2 x) = sin (\frac{π}{2} - x)

sin (x) = sin (5 0^{\circ})

n, y = - sin (2 (\frac{3 π}{4} + πn)) 2

tan (θ) = \frac{18}{7}

What is the general solution for 9(sin(x)-0.6pi)+8=0 ?
The general solution for 9(sin(x)-0.6pi)+8=0 is x=1.48207…+2pin,x=pi-1.48207…+2pin