What is the general solution for solvefor θ,z*p*cos(θ)=5 ?

The general solution for solvefor θ,z*p*cos(θ)=5 is θ=arccos(5/(zp))+2pin,θ=-arccos(5/(zp))+2pin

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solvefor θ,zpcos(θ)=5

solve for

θ, z \cdot p \cdot cos (θ) = 5

θ = arccos (\frac{5}{z p}) + 2 πn, θ = - arccos (\frac{5}{z p}) + 2 πn

Solution steps

z p cos (θ) = 5

Divide both sides by

z p; z \neq = 0

cos (θ) = \frac{5}{z p}; z \neq = 0

Apply trig inverse properties

θ = arccos (\frac{5}{z p}) + 2 πn, θ = - arccos (\frac{5}{z p}) + 2 πn

cos (4 x) + sin (2 x) = 0

sin (x + 5) = cos (2 x - 2)

θ, z \cdot p \cdot cos (θ) = n

tan (θ) = \frac{1}{5}, csc (θ)

6 = tan (6 C)

What is the general solution for solvefor θ,z*p*cos(θ)=5 ?
The general solution for solvefor θ,z*p*cos(θ)=5 is θ=arccos(5/(zp))+2pin,θ=-arccos(5/(zp))+2pin