What is the general solution for solvefor θ,z*p*cos(θ)=n ?

The general solution for solvefor θ,z*p*cos(θ)=n is θ=arccos(n/(zp))+2pik,θ=-arccos(n/(zp))+2pik

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solvefor θ,zpcos(θ)=n

solve for

θ, z \cdot p \cdot cos (θ) = n

θ = arccos (\frac{n}{z p}) + 2 πk, θ = - arccos (\frac{n}{z p}) + 2 πk

Solution steps

z p cos (θ) = n

Divide both sides by

z p; z \neq = 0

cos (θ) = \frac{n}{z p}; z \neq = 0

Apply trig inverse properties

θ = arccos (\frac{n}{z p}) + 2 πk, θ = - arccos (\frac{n}{z p}) + 2 πk

tan (θ) = \frac{1}{5}, csc (θ)

6 = tan (6 C)

\frac{3}{4} = tan (x)

cos (x) = - 3 + \frac{4}{cos ( x )}

sin (x) + 4 cos (x) + 5 = 0

What is the general solution for solvefor θ,z*p*cos(θ)=n ?
The general solution for solvefor θ,z*p*cos(θ)=n is θ=arccos(n/(zp))+2pik,θ=-arccos(n/(zp))+2pik