What is the general solution for 11csc(x)+15=9csc(x)+19 ?

The general solution for 11csc(x)+15=9csc(x)+19 is x= pi/6+2pin,x=(5pi)/6+2pin

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11csc(x)+15=9csc(x)+19

11 csc (x) + 15 = 9 csc (x) + 19

x = \frac{π}{6} + 2 πn, x = \frac{5 π}{6} + 2 πn

Solution steps

11 csc (x) + 15 = 9 csc (x) + 19

Solve by substitution

csc (x) = 2

csc (x) = 2 : x = \frac{π}{6} + 2 πn, x = \frac{5 π}{6} + 2 πn

Combine all the solutions

x = \frac{π}{6} + 2 πn, x = \frac{5 π}{6} + 2 πn

sin^{2} (x) = \frac{tan ( x )}{2}

98 \cdot sin (θ) - 19.6 \cdot cos (θ) = 75.1

\frac{( sin ( x ) + tan ( x ) )}{1 + cos ( x )} = m \cdot sec (x)

2 sin (2 x) - 2 sin (x) = 0

\frac{sin ( 2 5 ^{\circ} )}{5} = \frac{sin ( b )}{8}

What is the general solution for 11csc(x)+15=9csc(x)+19 ?
The general solution for 11csc(x)+15=9csc(x)+19 is x= pi/6+2pin,x=(5pi)/6+2pin