What is the general solution for 2sin(2x)-2sin(x)=0 ?

The general solution for 2sin(2x)-2sin(x)=0 is x=2pin,x=pi+2pin,x= pi/3+2pin,x=(5pi)/3+2pin

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2sin(2x)-2sin(x)=0

2 sin (2 x) - 2 sin (x) = 0

x = 2 πn, x = π + 2 πn, x = \frac{π}{3} + 2 πn, x = \frac{5 π}{3} + 2 πn

Solution steps

2 sin (2 x) - 2 sin (x) = 0

Rewrite using trig identities

- 2 sin (x) + 4 cos (x) sin (x) = 0

Factor

- 2 sin (x) + 4 cos (x) sin (x) : 2 sin (x) (2 cos (x) - 1)

2 sin (x) (2 cos (x) - 1) = 0

Solving each part separately

sin (x) = 0 or 2 cos (x) - 1 = 0

sin (x) = 0 : x = 2 πn, x = π + 2 πn

2 cos (x) - 1 = 0 : x = \frac{π}{3} + 2 πn, x = \frac{5 π}{3} + 2 πn

Combine all the solutions

x = 2 πn, x = π + 2 πn, x = \frac{π}{3} + 2 πn, x = \frac{5 π}{3} + 2 πn

\frac{sin ( 2 5 ^{\circ} )}{5} = \frac{sin ( b )}{8}

cos (x) - cos (3 x) = - 2 sin (x)

sin (x) + sin (5 x) = 0

sin^{2} (x) + cos^{2} (x) = tan (x)

3 tan (3 x) = tan (x)

What is the general solution for 2sin(2x)-2sin(x)=0 ?
The general solution for 2sin(2x)-2sin(x)=0 is x=2pin,x=pi+2pin,x= pi/3+2pin,x=(5pi)/3+2pin