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人気のある三角関数 >

(sin(25))/5 =(sin(b))/8

解

\frac{sin ( 2 5 ^{\circ} )}{5} = \frac{sin ( b )}{8}

解

b = 0.74257 \dots + 36 0^{\circ} n, b = 18 0^{\circ} - 0.74257 \dots + 36 0^{\circ} n

+1

ラジアン

b = 0.74257 \dots + 2 πn, b = π - 0.74257 \dots + 2 πn

解答ステップ

\frac{sin ( 2 5 ^{\circ} )}{5} = \frac{sin ( b )}{8}

辺を交換する

\frac{sin ( b )}{8} = \frac{sin ( 2 5 ^{\circ} )}{5}

以下で両辺を乗じる:

8

\frac{sin ( b )}{8} = \frac{sin ( 2 5 ^{\circ} )}{5}

以下で両辺を乗じる:

8

\frac{8 sin ( b )}{8} = \frac{8 sin ( 2 5 ^{\circ} )}{5}

簡素化

sin (b) = \frac{8 sin ( 2 5 ^{\circ} )}{5}

sin (b) = \frac{8 sin ( 2 5 ^{\circ} )}{5}

三角関数の逆数プロパティを適用する

sin (b) = \frac{8 sin ( 2 5 ^{\circ} )}{5}

以下の一般解

sin (b) = \frac{8 sin ( 2 5 ^{\circ} )}{5}

sin (x) = a \Rightarrow x = arcsin (a) + 36 0^{\circ} n, x = 18 0^{\circ} - arcsin (a) + 36 0^{\circ} n

b = arcsin (\frac{8 sin ( 2 5 ^{\circ} )}{5}) + 36 0^{\circ} n, b = 18 0^{\circ} - arcsin (\frac{8 sin ( 2 5 ^{\circ} )}{5}) + 36 0^{\circ} n

b = arcsin (\frac{8 sin ( 2 5 ^{\circ} )}{5}) + 36 0^{\circ} n, b = 18 0^{\circ} - arcsin (\frac{8 sin ( 2 5 ^{\circ} )}{5}) + 36 0^{\circ} n

10進法形式で解を証明する

b = 0.74257 \dots + 36 0^{\circ} n, b = 18 0^{\circ} - 0.74257 \dots + 36 0^{\circ} n

グラフ

人気の例

cos(x)-cos(3x)=-sqrt(2)sin(x)

cos (x) - cos (3 x) = - 2 sin (x)

sin(x)+sin(5x)=0

sin (x) + sin (5 x) = 0

sin^2(x)+cos^2(x)=tan(x)

sin^{2} (x) + cos^{2} (x) = tan (x)

3tan(3x)=tan(x)

3 tan (3 x) = tan (x)

sin(x)=(sqrt(5))/5 ,sin(2x)

sin (x) = \frac{5}{5}, sin (2 x)