What is the general solution for cos(θ)=cos(pi/(13)) ?

The general solution for cos(θ)=cos(pi/(13)) is θ=0.24166…+2pin,θ=2pi-0.24166…+2pin

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cos(θ)=cos(pi/(13))

cos (θ) = cos (\frac{π}{13})

θ = 0.24166 \dots + 2 πn, θ = 2 π - 0.24166 \dots + 2 πn

Solution steps

cos (θ) = cos (\frac{π}{13})

Apply trig inverse properties

θ = arccos (cos (\frac{π}{13})) + 2 πn, θ = 2 π - arccos (cos (\frac{π}{13})) + 2 πn

Show solutions in decimal form

θ = 0.24166 \dots + 2 πn, θ = 2 π - 0.24166 \dots + 2 πn

sin (2 x + \frac{π}{6}) = - 1

tan (x) = 2 π

2 sin^{2} (x) - 2 = 0

x, z = sin (5 x) y^{3}

8 tan^{2} (θ) - 1 = 3 tan (θ) + 4

What is the general solution for cos(θ)=cos(pi/(13)) ?
The general solution for cos(θ)=cos(pi/(13)) is θ=0.24166…+2pin,θ=2pi-0.24166…+2pin