What is the general solution for sin(2x+pi/6)=-1 ?

The general solution for sin(2x+pi/6)=-1 is x=pin+(2pi)/3

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sin(2x+pi/6)=-1

sin (2 x + \frac{π}{6}) = - 1

x = πn + \frac{2 π}{3}

Solution steps

sin (2 x + \frac{π}{6}) = - 1

General solutions for

sin (2 x + \frac{π}{6}) = - 1

2 x + \frac{π}{6} = \frac{3 π}{2} + 2 πn

Solve

2 x + \frac{π}{6} = \frac{3 π}{2} + 2 πn : x = πn + \frac{2 π}{3}

x = πn + \frac{2 π}{3}

tan (x) = 2 π

2 sin^{2} (x) - 2 = 0

x, z = sin (5 x) y^{3}

8 tan^{2} (θ) - 1 = 3 tan (θ) + 4

2 csc^{2} (x) + csc (x) - 2 = 0

What is the general solution for sin(2x+pi/6)=-1 ?
The general solution for sin(2x+pi/6)=-1 is x=pin+(2pi)/3