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Popular Trigonometry >

tan(x)=-24/7 tan(2x)

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Solution

tan(x)=−724​tan(2x)

Solution

x=πn,x=−1.22811…+πn,x=1.22811…+πn
+1
Degrees
x=0∘+180∘n,x=−70.36598…∘+180∘n,x=70.36598…∘+180∘n
Solution steps
tan(x)=−724​tan(2x)
Subtract −724​tan(2x) from both sidestan(x)+724​tan(2x)=0
Simplify tan(x)+724​tan(2x):77tan(x)+24tan(2x)​
tan(x)+724​tan(2x)
Multiply 724​tan(2x):724tan(2x)​
724​tan(2x)
Multiply fractions: a⋅cb​=ca⋅b​=724tan(2x)​
=tan(x)+724tan(2x)​
Convert element to fraction: tan(x)=7tan(x)7​=7tan(x)⋅7​+724tan(2x)​
Since the denominators are equal, combine the fractions: ca​±cb​=ca±b​=7tan(x)⋅7+24tan(2x)​
77tan(x)+24tan(2x)​=0
g(x)f(x)​=0⇒f(x)=07tan(x)+24tan(2x)=0
Rewrite using trig identities
24tan(2x)+7tan(x)
Use the Double Angle identity: tan(2x)=1−tan2(x)2tan(x)​=24⋅1−tan2(x)2tan(x)​+7tan(x)
Simplify 24⋅1−tan2(x)2tan(x)​+7tan(x):1−tan2(x)55tan(x)−7tan3(x)​
24⋅1−tan2(x)2tan(x)​+7tan(x)
24⋅1−tan2(x)2tan(x)​=1−tan2(x)48tan(x)​
24⋅1−tan2(x)2tan(x)​
Multiply fractions: a⋅cb​=ca⋅b​=1−tan2(x)2tan(x)⋅24​
Multiply the numbers: 2⋅24=48=1−tan2(x)48tan(x)​
=−tan2(x)+148tan(x)​+7tan(x)
Convert element to fraction: 7tan(x)=1−tan2(x)7tan(x)(1−tan2(x))​=1−tan2(x)48tan(x)​+1−tan2(x)7tan(x)(1−tan2(x))​
Since the denominators are equal, combine the fractions: ca​±cb​=ca±b​=1−tan2(x)48tan(x)+7tan(x)(1−tan2(x))​
Expand 48tan(x)+7tan(x)(1−tan2(x)):55tan(x)−7tan3(x)
48tan(x)+7tan(x)(1−tan2(x))
Expand 7tan(x)(1−tan2(x)):7tan(x)−7tan3(x)
7tan(x)(1−tan2(x))
Apply the distributive law: a(b−c)=ab−aca=7tan(x),b=1,c=tan2(x)=7tan(x)⋅1−7tan(x)tan2(x)
=7⋅1⋅tan(x)−7tan2(x)tan(x)
Simplify 7⋅1⋅tan(x)−7tan2(x)tan(x):7tan(x)−7tan3(x)
7⋅1⋅tan(x)−7tan2(x)tan(x)
7⋅1⋅tan(x)=7tan(x)
7⋅1⋅tan(x)
Multiply the numbers: 7⋅1=7=7tan(x)
7tan2(x)tan(x)=7tan3(x)
7tan2(x)tan(x)
Apply exponent rule: ab⋅ac=ab+ctan2(x)tan(x)=tan2+1(x)=7tan2+1(x)
Add the numbers: 2+1=3=7tan3(x)
=7tan(x)−7tan3(x)
=7tan(x)−7tan3(x)
=48tan(x)+7tan(x)−7tan3(x)
Add similar elements: 48tan(x)+7tan(x)=55tan(x)=55tan(x)−7tan3(x)
=1−tan2(x)55tan(x)−7tan3(x)​
=1−tan2(x)55tan(x)−7tan3(x)​
1−tan2(x)55tan(x)−7tan3(x)​=0
Solve by substitution
1−tan2(x)55tan(x)−7tan3(x)​=0
Let: tan(x)=u1−u255u−7u3​=0
1−u255u−7u3​=0:u=0,u=−755​​,u=755​​
1−u255u−7u3​=0
g(x)f(x)​=0⇒f(x)=055u−7u3=0
Solve 55u−7u3=0:u=0,u=−755​​,u=755​​
55u−7u3=0
Factor 55u−7u3:−u(7​u+55​)(7​u−55​)
55u−7u3
Factor out common term −u:−u(7u2−55)
−7u3+55u
Apply exponent rule: ab+c=abacu3=u2u=−7u2u+55u
Factor out common term −u=−u(7u2−55)
=−u(7u2−55)
Factor 7u2−55:(7​u+55​)(7​u−55​)
7u2−55
Rewrite 7u2−55 as (7​u)2−(55​)2
7u2−55
Apply radical rule: a=(a​)27=(7​)2=(7​)2u2−55
Apply radical rule: a=(a​)255=(55​)2=(7​)2u2−(55​)2
Apply exponent rule: ambm=(ab)m(7​)2u2=(7​u)2=(7​u)2−(55​)2
=(7​u)2−(55​)2
Apply Difference of Two Squares Formula: x2−y2=(x+y)(x−y)(7​u)2−(55​)2=(7​u+55​)(7​u−55​)=(7​u+55​)(7​u−55​)
=−u(7​u+55​)(7​u−55​)
−u(7​u+55​)(7​u−55​)=0
Using the Zero Factor Principle: If ab=0then a=0or b=0u=0or7​u+55​=0or7​u−55​=0
Solve 7​u+55​=0:u=−755​​
7​u+55​=0
Move 55​to the right side
7​u+55​=0
Subtract 55​ from both sides7​u+55​−55​=0−55​
Simplify7​u=−55​
7​u=−55​
Divide both sides by 7​
7​u=−55​
Divide both sides by 7​7​7​u​=7​−55​​
Simplify
7​7​u​=7​−55​​
Simplify 7​7​u​:u
7​7​u​
Cancel the common factor: 7​=u
Simplify 7​−55​​:−755​​
7​−55​​
Apply the fraction rule: b−a​=−ba​=−7​55​​
Combine same powers : y​x​​=yx​​=−755​​
u=−755​​
u=−755​​
u=−755​​
Solve 7​u−55​=0:u=755​​
7​u−55​=0
Move 55​to the right side
7​u−55​=0
Add 55​ to both sides7​u−55​+55​=0+55​
Simplify7​u=55​
7​u=55​
Divide both sides by 7​
7​u=55​
Divide both sides by 7​7​7​u​=7​55​​
Simplify
7​7​u​=7​55​​
Simplify 7​7​u​:u
7​7​u​
Cancel the common factor: 7​=u
Simplify 7​55​​:755​​
7​55​​
Combine same powers : y​x​​=yx​​=755​​
u=755​​
u=755​​
u=755​​
The solutions areu=0,u=−755​​,u=755​​
u=0,u=−755​​,u=755​​
Verify Solutions
Find undefined (singularity) points:u=1,u=−1
Take the denominator(s) of 1−u255u−7u3​ and compare to zero
Solve 1−u2=0:u=1,u=−1
1−u2=0
Move 1to the right side
1−u2=0
Subtract 1 from both sides1−u2−1=0−1
Simplify−u2=−1
−u2=−1
Divide both sides by −1
−u2=−1
Divide both sides by −1−1−u2​=−1−1​
Simplifyu2=1
u2=1
For x2=f(a) the solutions are x=f(a)​,−f(a)​
u=1​,u=−1​
1​=1
1​
Apply radical rule: 1​=1=1
−1​=−1
−1​
Apply radical rule: 1​=11​=1=−1
u=1,u=−1
The following points are undefinedu=1,u=−1
Combine undefined points with solutions:
u=0,u=−755​​,u=755​​
Substitute back u=tan(x)tan(x)=0,tan(x)=−755​​,tan(x)=755​​
tan(x)=0,tan(x)=−755​​,tan(x)=755​​
tan(x)=0:x=πn
tan(x)=0
General solutions for tan(x)=0
tan(x) periodicity table with πn cycle:
x06π​4π​3π​2π​32π​43π​65π​​tan(x)033​​13​±∞−3​−1−33​​​​
x=0+πn
x=0+πn
Solve x=0+πn:x=πn
x=0+πn
0+πn=πnx=πn
x=πn
tan(x)=−755​​:x=arctan(−755​​)+πn
tan(x)=−755​​
Apply trig inverse properties
tan(x)=−755​​
General solutions for tan(x)=−755​​tan(x)=−a⇒x=arctan(−a)+πnx=arctan(−755​​)+πn
x=arctan(−755​​)+πn
tan(x)=755​​:x=arctan(755​​)+πn
tan(x)=755​​
Apply trig inverse properties
tan(x)=755​​
General solutions for tan(x)=755​​tan(x)=a⇒x=arctan(a)+πnx=arctan(755​​)+πn
x=arctan(755​​)+πn
Combine all the solutionsx=πn,x=arctan(−755​​)+πn,x=arctan(755​​)+πn
Show solutions in decimal formx=πn,x=−1.22811…+πn,x=1.22811…+πn

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Frequently Asked Questions (FAQ)

  • What is the general solution for tan(x)=-24/7 tan(2x) ?

    The general solution for tan(x)=-24/7 tan(2x) is x=pin,x=-1.22811…+pin,x=1.22811…+pin
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