What is the general solution for 2=4cos(3x+1) ?

The general solution for 2=4cos(3x+1) is x=-1/3+pi/9+(2pin)/3 ,x=-1/3+(5pi)/9+(2pin)/3

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2=4cos(3x+1)

2 = 4 cos (3 x + 1)

x = - \frac{1}{3} + \frac{π}{9} + \frac{2 πn}{3}, x = - \frac{1}{3} + \frac{5 π}{9} + \frac{2 πn}{3}

Solution steps

2 = 4 cos (3 x + 1)

Switch sides

4 cos (3 x + 1) = 2

Divide both sides by

4

cos (3 x + 1) = \frac{1}{2}

General solutions for

cos (3 x + 1) = \frac{1}{2}

3 x + 1 = \frac{π}{3} + 2 πn, 3 x + 1 = \frac{5 π}{3} + 2 πn

Solve

3 x + 1 = \frac{π}{3} + 2 πn : x = - \frac{1}{3} + \frac{π}{9} + \frac{2 πn}{3}

Solve

3 x + 1 = \frac{5 π}{3} + 2 πn : x = - \frac{1}{3} + \frac{5 π}{9} + \frac{2 πn}{3}

x = - \frac{1}{3} + \frac{π}{9} + \frac{2 πn}{3}, x = - \frac{1}{3} + \frac{5 π}{9} + \frac{2 πn}{3}

tan (x) = \frac{13}{6}

3 sinh (2 x) = 5

sin (\frac{x}{25.4}) = 35

\frac{2}{3} = \frac{sin ( x )}{sin ( 13 5 ^{\circ} )}

sin (x) + 2 (cos (x))^{2} = 1

What is the general solution for 2=4cos(3x+1) ?
The general solution for 2=4cos(3x+1) is x=-1/3+pi/9+(2pin)/3 ,x=-1/3+(5pi)/9+(2pin)/3