What is the general solution for sin(α)=(120sin(60))/(1200) ?

The general solution for sin(α)=(120sin(60))/(1200) is α=0.08671…+360n,α=180-0.08671…+360n

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sin(α)=(120sin(60))/(1200)

sin (α) = \frac{120 sin ( 6 0 ^{\circ} )}{1200}

α = 0.08671 \dots + 36 0^{\circ} n, α = 18 0^{\circ} - 0.08671 \dots + 36 0^{\circ} n

Solution steps

sin (α) = \frac{120 sin ( 6 0 ^{\circ} )}{1200}

sin (6 0^{\circ}) = \frac{3}{2}

sin (α) = \frac{120 \cdot \frac{3}{2}}{1200}

Simplify

\frac{120 \cdot \frac{3}{2}}{1200} : \frac{3}{20}

Apply trig inverse properties

α = arcsin (\frac{3}{20}) + 36 0^{\circ} n, α = 18 0^{\circ} - arcsin (\frac{3}{20}) + 36 0^{\circ} n

Show solutions in decimal form

α = 0.08671 \dots + 36 0^{\circ} n, α = 18 0^{\circ} - 0.08671 \dots + 36 0^{\circ} n

15.8 \cdot sin (30 x - 90) + 5 = 17

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cos^{2} (θ) - 1 = sin^{2} (θ)

- 3 cos^{2} (u) sin (u) - 2 sin (2 u) = 0

cot (θ) = - \frac{7}{24}

What is the general solution for sin(α)=(120sin(60))/(1200) ?
The general solution for sin(α)=(120sin(60))/(1200) is α=0.08671…+360n,α=180-0.08671…+360n