What is the general solution for cos^2(θ)-1=sin^2(θ) ?

The general solution for cos^2(θ)-1=sin^2(θ) is θ=pin

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cos^2(θ)-1=sin^2(θ)

cos^{2} (θ) - 1 = sin^{2} (θ)

θ = πn

Solution steps

cos^{2} (θ) - 1 = sin^{2} (θ)

Subtract

sin^{2} (θ)

from both sides

cos^{2} (θ) - 1 - sin^{2} (θ) = 0

Rewrite using trig identities

- 1 + cos (2 θ) = 0

Move

1

to the right side

cos (2 θ) = 1

General solutions for

cos (2 θ) = 1

2 θ = 0 + 2 πn

Solve

2 θ = 0 + 2 πn : θ = πn

θ = πn

- 3 cos^{2} (u) sin (u) - 2 sin (2 u) = 0

cot (θ) = - \frac{7}{24}

2 sin (x) + 2 cos (x) = 6

0 = - 0.65 sin (13 x)

x, tan^{2} (x) - 1 = 0

What is the general solution for cos^2(θ)-1=sin^2(θ) ?
The general solution for cos^2(θ)-1=sin^2(θ) is θ=pin