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受欢迎的三角函数 >

(15-sqrt(3))/3 =5-2/3*csc(4x+pi/2)

解答

\frac{15 - 3}{3} = 5 - \frac{2}{3} \cdot csc (4 x + \frac{π}{2})

解答

x \in R 无解

求解步骤

\frac{15 - 3}{3} = 5 - \frac{2}{3} csc (4 x + \frac{π}{2})

交换两边

5 - \frac{2}{3} csc (4 x + \frac{π}{2}) = \frac{15 - 3}{3}

将

5

到右边

5 - \frac{2}{3} csc (4 x + \frac{π}{2}) = \frac{15 - 3}{3}

两边减去

5

5 - \frac{2}{3} csc (4 x + \frac{π}{2}) - 5 = \frac{15 - 3}{3} - 5

化简

- \frac{2}{3} csc (4 x + \frac{π}{2}) = \frac{15 - 3}{3} - 5

- \frac{2}{3} csc (4 x + \frac{π}{2}) = \frac{15 - 3}{3} - 5

在两边乘以

3

- \frac{2}{3} csc (4 x + \frac{π}{2}) = \frac{15 - 3}{3} - 5

在两边乘以

3

3 (- \frac{2}{3} csc (4 x + \frac{π}{2})) = 3 \cdot \frac{15 - 3}{3} - 3 \cdot 5

化简

3 (- \frac{2}{3} csc (4 x + \frac{π}{2})) = 3 \cdot \frac{15 - 3}{3} - 3 \cdot 5

化简

3 (- \frac{2}{3} csc (4 x + \frac{π}{2})) : - 2 csc (4 x + \frac{π}{2})

3 (- \frac{2}{3} csc (4 x + \frac{π}{2}))

去除括号:

(- a) = - a

= - 3 \cdot \frac{2}{3} csc (4 x + \frac{π}{2})

分式相乘:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= - \frac{2 \cdot 3}{3} csc (4 x + \frac{π}{2})

约分:

3

= - csc (4 x + \frac{π}{2}) \cdot 2

化简

3 \cdot \frac{15 - 3}{3} - 3 \cdot 5 : - 3

3 \cdot \frac{15 - 3}{3} - 3 \cdot 5

3 \cdot \frac{15 - 3}{3} = 15 - 3

3 \cdot \frac{15 - 3}{3}

分式相乘:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( 15 - 3 ) \cdot 3}{3}

约分:

3

= 15 - 3

3 \cdot 5 = 15

3 \cdot 5

数字相乘:

3 \cdot 5 = 15

= 15

= 15 - 3 - 15

15 - 15 = 0

= - 3

- 2 csc (4 x + \frac{π}{2}) = - 3

- 2 csc (4 x + \frac{π}{2}) = - 3

- 2 csc (4 x + \frac{π}{2}) = - 3

两边除以

- 2

- 2 csc (4 x + \frac{π}{2}) = - 3

两边除以

- 2

\frac{- 2 csc ( 4 x + \frac{π}{2} )}{- 2} = \frac{- 3}{- 2}

化简

csc (4 x + \frac{π}{2}) = \frac{3}{2}

csc (4 x + \frac{π}{2}) = \frac{3}{2}

csc (x) \leq - 1 or csc (x) \geq 1

x \in R 无解

作图

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