What is the general solution for -5sin(2t)=0 ?

The general solution for -5sin(2t)=0 is t=pin,t= pi/2+pin

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-5sin(2t)=0

- 5 sin (2 t) = 0

t = πn, t = \frac{π}{2} + πn

Solution steps

- 5 sin (2 t) = 0

Divide both sides by

- 5

sin (2 t) = 0

General solutions for

sin (2 t) = 0

2 t = 0 + 2 πn, 2 t = π + 2 πn

Solve

2 t = 0 + 2 πn : t = πn

Solve

2 t = π + 2 πn : t = \frac{π}{2} + πn

t = πn, t = \frac{π}{2} + πn

(cos (x) - 1) = 0

1 + cot^{2} (a) = tan^{2} (a)

tan (α) = \frac{12}{6 3}

1 = cos^{2} (α) - 2 cos (α) sin (a) + sin^{2} (α)

4 sin (θ) = 1

What is the general solution for -5sin(2t)=0 ?
The general solution for -5sin(2t)=0 is t=pin,t= pi/2+pin