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人気のある三角関数 >

cos^2(θ)+(10^2)/(9.81(1))cos(θ)-1=0

解

cos^{2} (θ) + \frac{1 0 ^{2}}{9.81 ( 1 )} cos (θ) - 1 = 0

解

θ = 1.47346 \dots + 2 πn, θ = 2 π - 1.47346 \dots + 2 πn

+1

度

θ = 84.42355 \dots^{\circ} + 36 0^{\circ} n, θ = 275.57644 \dots^{\circ} + 36 0^{\circ} n

解答ステップ

cos^{2} (θ) + \frac{1 0 ^{2}}{9.81 ( 1 )} cos (θ) - 1 = 0

置換で解く

cos^{2} (θ) + \frac{1 0 ^{2}}{9.81 \cdot 1} cos (θ) - 1 = 0

仮定:

cos (θ) = u

u^{2} + \frac{1 0 ^{2}}{9.81 \cdot 1} u - 1 = 0

u^{2} + \frac{1 0 ^{2}}{9.81 \cdot 1} u - 1 = 0 : u = \frac{- 100 + 10384.9444}{19.62}, u = \frac{- 100 - 10384.9444}{19.62}

u^{2} + \frac{1 0 ^{2}}{9.81 \cdot 1} u - 1 = 0

以下で両辺を乗じる:

9.81

u^{2} + \frac{1 0 ^{2}}{9.81 \cdot 1} u - 1 = 0

以下で両辺を乗じる:

9.81

u^{2} \cdot 9.81 + \frac{1 0 ^{2}}{9.81 \cdot 1} u \cdot 9.81 - 1 \cdot 9.81 = 0 \cdot 9.81

簡素化

9.81 u^{2} + 100 u - 9.81 = 0

9.81 u^{2} + 100 u - 9.81 = 0

解くとthe二次式

9.81 u^{2} + 100 u - 9.81 = 0

二次Equationの公式:

次の場合:

a = 9.81, b = 100, c = - 9.81

u_{1, 2} = \frac{- 100 \pm 10 0 ^{2} - 4 \cdot 9.81 ( - 9.81 )}{2 \cdot 9.81}

u_{1, 2} = \frac{- 100 \pm 10 0 ^{2} - 4 \cdot 9.81 ( - 9.81 )}{2 \cdot 9.81}

10 0^{2} - 4 \cdot 9.81 (- 9.81) = 10384.9444

10 0^{2} - 4 \cdot 9.81 (- 9.81)

規則を適用

- (- a) = a

= 10 0^{2} + 4 \cdot 9.81 \cdot 9.81

数を乗じる:

4 \cdot 9.81 \cdot 9.81 = 384.9444

= 10 0^{2} + 384.9444

10 0^{2} = 10000

= 10000 + 384.9444

数を足す:

10000 + 384.9444 = 10384.9444

= 10384.9444

u_{1, 2} = \frac{- 100 \pm 10384.9444}{2 \cdot 9.81}

解を分離する

u_{1} = \frac{- 100 + 10384.9444}{2 \cdot 9.81}, u_{2} = \frac{- 100 - 10384.9444}{2 \cdot 9.81}

u = \frac{- 100 + 10384.9444}{2 \cdot 9.81} : \frac{- 100 + 10384.9444}{19.62}

\frac{- 100 + 10384.9444}{2 \cdot 9.81}

数を乗じる:

2 \cdot 9.81 = 19.62

= \frac{- 100 + 10384.9444}{19.62}

u = \frac{- 100 - 10384.9444}{2 \cdot 9.81} : \frac{- 100 - 10384.9444}{19.62}

\frac{- 100 - 10384.9444}{2 \cdot 9.81}

数を乗じる:

2 \cdot 9.81 = 19.62

= \frac{- 100 - 10384.9444}{19.62}

二次equationの解:

u = \frac{- 100 + 10384.9444}{19.62}, u = \frac{- 100 - 10384.9444}{19.62}

代用を戻す

u = cos (θ)

cos (θ) = \frac{- 100 + 10384.9444}{19.62}, cos (θ) = \frac{- 100 - 10384.9444}{19.62}

cos (θ) = \frac{- 100 + 10384.9444}{19.62}, cos (θ) = \frac{- 100 - 10384.9444}{19.62}

cos (θ) = \frac{- 100 + 10384.9444}{19.62} : θ = arccos (\frac{- 100 + 10384.9444}{19.62}) + 2 πn, θ = 2 π - arccos (\frac{- 100 + 10384.9444}{19.62}) + 2 πn

cos (θ) = \frac{- 100 + 10384.9444}{19.62}

三角関数の逆数プロパティを適用する

cos (θ) = \frac{- 100 + 10384.9444}{19.62}

以下の一般解

cos (θ) = \frac{- 100 + 10384.9444}{19.62}

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = 2 π - arccos (a) + 2 πn

θ = arccos (\frac{- 100 + 10384.9444}{19.62}) + 2 πn, θ = 2 π - arccos (\frac{- 100 + 10384.9444}{19.62}) + 2 πn

θ = arccos (\frac{- 100 + 10384.9444}{19.62}) + 2 πn, θ = 2 π - arccos (\frac{- 100 + 10384.9444}{19.62}) + 2 πn

cos (θ) = \frac{- 100 - 10384.9444}{19.62} :

解なし

cos (θ) = \frac{- 100 - 10384.9444}{19.62}

- 1 \leq cos (x) \leq 1

解なし

すべての解を組み合わせる

θ = arccos (\frac{- 100 + 10384.9444}{19.62}) + 2 πn, θ = 2 π - arccos (\frac{- 100 + 10384.9444}{19.62}) + 2 πn

10進法形式で解を証明する

θ = 1.47346 \dots + 2 πn, θ = 2 π - 1.47346 \dots + 2 πn

グラフ

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