What is the general solution for cos^2(θ)+(10^2)/(9.81(1))cos(θ)-1=0 ?

The general solution for cos^2(θ)+(10^2)/(9.81(1))cos(θ)-1=0 is θ=1.47346…+2pin,θ=2pi-1.47346…+2pin

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cos^2(θ)+(10^2)/(9.81(1))cos(θ)-1=0

cos^{2} (θ) + \frac{1 0 ^{2}}{9.81 ( 1 )} cos (θ) - 1 = 0

θ = 1.47346 \dots + 2 πn, θ = 2 π - 1.47346 \dots + 2 πn

Solution steps

cos^{2} (θ) + \frac{1 0 ^{2}}{9.81 ( 1 )} cos (θ) - 1 = 0

Solve by substitution

cos (θ) = \frac{- 100 + 10384.9444}{19.62}, cos (θ) = \frac{- 100 - 10384.9444}{19.62}

cos (θ) = \frac{- 100 + 10384.9444}{19.62} : θ = arccos (\frac{- 100 + 10384.9444}{19.62}) + 2 πn, θ = 2 π - arccos (\frac{- 100 + 10384.9444}{19.62}) + 2 πn

cos (θ) = \frac{- 100 - 10384.9444}{19.62} :

No Solution

Combine all the solutions

θ = arccos (\frac{- 100 + 10384.9444}{19.62}) + 2 πn, θ = 2 π - arccos (\frac{- 100 + 10384.9444}{19.62}) + 2 πn

Show solutions in decimal form

θ = 1.47346 \dots + 2 πn, θ = 2 π - 1.47346 \dots + 2 πn

cos^{4} (x) = \frac{1}{16}

w, P = 4 (\frac{Y}{P sin ( w )})

tan (2 θ) = \frac{500}{350 - 75}

sec (a) = - 2

tan^{2} (γ) + 1 = cos^{2} (γ)

What is the general solution for cos^2(θ)+(10^2)/(9.81(1))cos(θ)-1=0 ?
The general solution for cos^2(θ)+(10^2)/(9.81(1))cos(θ)-1=0 is θ=1.47346…+2pin,θ=2pi-1.47346…+2pin