What is the general solution for solvefor x,cos(3x+pi/4)= 1/(sqrt(2)) ?

The general solution for solvefor x,cos(3x+pi/4)= 1/(sqrt(2)) is x=(2pin)/3 ,x=(2pin)/3+pi/2

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solvefor x,cos(3x+pi/4)= 1/(sqrt(2))

solve for

x, cos (3 x + \frac{π}{4}) = \frac{1}{2}

x = \frac{2 πn}{3}, x = \frac{2 πn}{3} + \frac{π}{2}

Solution steps

cos (3 x + \frac{π}{4}) = \frac{1}{2}

Simplify

\frac{1}{2} : \frac{2}{2}

General solutions for

cos (3 x + \frac{π}{4}) = \frac{2}{2}

3 x + \frac{π}{4} = \frac{π}{4} + 2 πn, 3 x + \frac{π}{4} = \frac{7 π}{4} + 2 πn

Solve

3 x + \frac{π}{4} = \frac{π}{4} + 2 πn : x = \frac{2 πn}{3}

Solve

3 x + \frac{π}{4} = \frac{7 π}{4} + 2 πn : x = \frac{2 πn}{3} + \frac{π}{2}

x = \frac{2 πn}{3}, x = \frac{2 πn}{3} + \frac{π}{2}

0 = 2 - 3 \cdot sin (x) - (cos^{2} (x) - sin^{2} (x))

x, cos^{2} (3 x + \frac{π}{4}) = \frac{3}{4}

\frac{tan ( x ^{2} + 6 ) - 1}{tan ( x )} = 0

tan (θ) = \frac{8}{- 8}

4 cos^{2} (x) + 4 sin (x) = 5

What is the general solution for solvefor x,cos(3x+pi/4)= 1/(sqrt(2)) ?
The general solution for solvefor x,cos(3x+pi/4)= 1/(sqrt(2)) is x=(2pin)/3 ,x=(2pin)/3+pi/2