What is the general solution for sin(3x+1)= 1/2 ?

The general solution for sin(3x+1)= 1/2 is x=-1/3+pi/(18)+(2pin)/3 ,x=-1/3+(5pi}{18}+\frac{2pin)/3

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sin(3x+1)= 1/2

sin (3 x + 1) = \frac{1}{2}

x = - \frac{1}{3} + \frac{π}{18} + \frac{2 πn}{3}, x = - \frac{1}{3} + \frac{5 π}{18} + \frac{2 πn}{3}

Solution steps

sin (3 x + 1) = \frac{1}{2}

General solutions for

sin (3 x + 1) = \frac{1}{2}

3 x + 1 = \frac{π}{6} + 2 πn, 3 x + 1 = \frac{5 π}{6} + 2 πn

Solve

3 x + 1 = \frac{π}{6} + 2 πn : x = - \frac{1}{3} + \frac{π}{18} + \frac{2 πn}{3}

Solve

3 x + 1 = \frac{5 π}{6} + 2 πn : x = - \frac{1}{3} + \frac{5 π}{18} + \frac{2 πn}{3}

x = - \frac{1}{3} + \frac{π}{18} + \frac{2 πn}{3}, x = - \frac{1}{3} + \frac{5 π}{18} + \frac{2 πn}{3}

cos (x) = \frac{1 3 ^{2} + 1 8 ^{2} - 2 8 ^{2}}{2 \cdot 13 \cdot 18}

0.16085 = sin (\frac{2 π}{365} (x - 114))

sin (x) = - \frac{8}{17}, π \leq x \leq \frac{3 π}{2}, sin (2 x)

tan (θ) cos (2 7^{\circ}) = cos (6 3^{\circ})

3 - sin (x) = cos (2 x)

What is the general solution for sin(3x+1)= 1/2 ?
The general solution for sin(3x+1)= 1/2 is x=-1/3+pi/(18)+(2pin)/3 ,x=-1/3+(5pi}{18}+\frac{2pin)/3