What is the general solution for sin(u)=-0.9 ?

The general solution for sin(u)=-0.9 is u=-1.11976…+2pin,u=pi+1.11976…+2pin

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sin(u)=-0.9

sin (u) = - 0.9

u = - 1.11976 \dots + 2 πn, u = π + 1.11976 \dots + 2 πn

Solution steps

sin (u) = - 0.9

Apply trig inverse properties

u = arcsin (- 0.9) + 2 πn, u = π + arcsin (0.9) + 2 πn

Show solutions in decimal form

u = - 1.11976 \dots + 2 πn, u = π + 1.11976 \dots + 2 πn

- \frac{3}{2} = - \frac{1}{2} sec (x)

sin (3 x + 1) = \frac{1}{2}

cos (x) = \frac{1 3 ^{2} + 1 8 ^{2} - 2 8 ^{2}}{2 \cdot 13 \cdot 18}

0.16085 = sin (\frac{2 π}{365} (x - 114))

sin (x) = - \frac{8}{17}, π \leq x \leq \frac{3 π}{2}, sin (2 x)

What is the general solution for sin(u)=-0.9 ?
The general solution for sin(u)=-0.9 is u=-1.11976…+2pin,u=pi+1.11976…+2pin