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受欢迎的三角函数 >

cos(a)=sin(a+30)

解答

cos (a) = sin (a + 3 0^{\circ})

解答

a = 3 0^{\circ} + 18 0^{\circ} n

+1

弧度

a = \frac{π}{6} + πn

求解步骤

cos (a) = sin (a + 3 0^{\circ})

使用三角恒等式改写

cos (a) = sin (a + 3 0^{\circ})

使用三角恒等式改写

sin (a + 3 0^{\circ})

使用角和恒等式:

sin (s + t) = sin (s) cos (t) + cos (s) sin (t)

= sin (a) cos (3 0^{\circ}) + cos (a) sin (3 0^{\circ})

化简

sin (a) cos (3 0^{\circ}) + cos (a) sin (3 0^{\circ}) : \frac{3}{2} sin (a) + \frac{1}{2} cos (a)

sin (a) cos (3 0^{\circ}) + cos (a) sin (3 0^{\circ})

化简

cos (3 0^{\circ}) : \frac{3}{2}

cos (3 0^{\circ})

使用以下普通恒等式:

cos (3 0^{\circ}) = \frac{3}{2}

cos (x)

周期表（周期为

36 0^{\circ} n

）：

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x 18 0^{\circ} 21 0^{\circ} 22 5^{\circ} 24 0^{\circ} 27 0^{\circ} 30 0^{\circ} 31 5^{\circ} 33 0^{\circ} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

= \frac{3}{2}

= \frac{3}{2} sin (a) + sin (3 0^{\circ}) cos (a)

化简

sin (3 0^{\circ}) : \frac{1}{2}

sin (3 0^{\circ})

使用以下普通恒等式:

sin (3 0^{\circ}) = \frac{1}{2}

sin (x)

周期表（周期为

36 0^{\circ} n

"）：

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x 18 0^{\circ} 21 0^{\circ} 22 5^{\circ} 24 0^{\circ} 27 0^{\circ} 30 0^{\circ} 31 5^{\circ} 33 0^{\circ} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= \frac{1}{2}

= \frac{3}{2} sin (a) + \frac{1}{2} cos (a)

= \frac{3}{2} sin (a) + \frac{1}{2} cos (a)

cos (a) = \frac{3}{2} sin (a) + \frac{1}{2} cos (a)

cos (a) = \frac{3}{2} sin (a) + \frac{1}{2} cos (a)

两边减去

\frac{3}{2} sin (a) + \frac{1}{2} cos (a)

\frac{1}{2} cos (a) - \frac{3}{2} sin (a) = 0

化简

\frac{1}{2} cos (a) - \frac{3}{2} sin (a) : \frac{cos ( a ) - 3 sin ( a )}{2}

\frac{1}{2} cos (a) - \frac{3}{2} sin (a)

\frac{1}{2} cos (a) = \frac{cos ( a )}{2}

\frac{1}{2} cos (a)

分式相乘:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot cos ( a )}{2}

乘以:

1 \cdot cos (a) = cos (a)

= \frac{cos ( a )}{2}

\frac{3}{2} sin (a) = \frac{3 sin ( a )}{2}

\frac{3}{2} sin (a)

分式相乘:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{3 sin ( a )}{2}

= \frac{cos ( a )}{2} - \frac{3 sin ( a )}{2}

使用法则

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{cos ( a ) - 3 sin ( a )}{2}

\frac{cos ( a ) - 3 sin ( a )}{2} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

cos (a) - 3 sin (a) = 0

使用三角恒等式改写

cos (a) - 3 sin (a) = 0

在两边除以

cos (a), cos (a) \neq = 0

\frac{cos ( a ) - 3 sin ( a )}{cos ( a )} = \frac{0}{cos ( a )}

化简

1 - \frac{3 sin ( a )}{cos ( a )} = 0

使用基本三角恒等式:

\frac{sin ( x )}{cos ( x )} = tan (x)

1 - 3 tan (a) = 0

1 - 3 tan (a) = 0

将

1

到右边

1 - 3 tan (a) = 0

两边减去

1

1 - 3 tan (a) - 1 = 0 - 1

化简

- 3 tan (a) = - 1

- 3 tan (a) = - 1

两边除以

- 3

- 3 tan (a) = - 1

两边除以

- 3

\frac{- 3 tan ( a )}{- 3} = \frac{- 1}{- 3}

化简

\frac{- 3 tan ( a )}{- 3} = \frac{- 1}{- 3}

化简

\frac{- 3 tan ( a )}{- 3} : tan (a)

\frac{- 3 tan ( a )}{- 3}

使用分式法则:

\frac{- a}{- b} = \frac{a}{b}

= \frac{3 tan ( a )}{3}

约分:

3

= tan (a)

化简

\frac{- 1}{- 3} : \frac{3}{3}

\frac{- 1}{- 3}

使用分式法则:

\frac{- a}{- b} = \frac{a}{b}

= \frac{1}{3}

\frac{1}{3}

有理化:

\frac{3}{3}

\frac{1}{3}

乘以共轭根式

\frac{3}{3}

= \frac{1 \cdot 3}{3 3}

1 \cdot 3 = 3

33 = 3

33

使用根式运算法则:

a a = a

33 = 3

= 3

= \frac{3}{3}

= \frac{3}{3}

tan (a) = \frac{3}{3}

tan (a) = \frac{3}{3}

tan (a) = \frac{3}{3}

tan (a) = \frac{3}{3}

的通解

tan (x)

周期表（周期为

18 0^{\circ} n

）：

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

a = 3 0^{\circ} + 18 0^{\circ} n

a = 3 0^{\circ} + 18 0^{\circ} n

作图

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