What is the general solution for 0=1+sin(θ) ?

The general solution for 0=1+sin(θ) is θ=(3pi)/2+2pin

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0=1+sin(θ)

0 = 1 + sin (θ)

θ = \frac{3 π}{2} + 2 πn

Solution steps

0 = 1 + sin (θ)

Switch sides

1 + sin (θ) = 0

Move

1

to the right side

sin (θ) = - 1

General solutions for

sin (θ) = - 1

θ = \frac{3 π}{2} + 2 πn

2 cos (2 x) - cos (x) - 1 = 0

tan (x) \cdot tan (2 x) = 1

cos (x) cot (x) - 3 (1 - sin (x)) = 0

18 = \frac{1}{2} \cdot 9 \cdot 5 \cdot sin (θ)

2 cos^{2} (x) = cos^{2} (x)

What is the general solution for 0=1+sin(θ) ?
The general solution for 0=1+sin(θ) is θ=(3pi)/2+2pin