What is the general solution for tan(60-θ)= 1/(sqrt(3)) ?

The general solution for tan(60-θ)= 1/(sqrt(3)) is θ=-180n+30

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tan(60-θ)= 1/(sqrt(3))

tan (6 0^{\circ} - θ) = \frac{1}{3}

θ = - 18 0^{\circ} n + 3 0^{\circ}

Solution steps

tan (6 0^{\circ} - θ) = \frac{1}{3}

Simplify

\frac{1}{3} : \frac{3}{3}

General solutions for

tan (6 0^{\circ} - θ) = \frac{3}{3}

6 0^{\circ} - θ = 3 0^{\circ} + 18 0^{\circ} n

Solve

6 0^{\circ} - θ = 3 0^{\circ} + 18 0^{\circ} n : θ = - 18 0^{\circ} n + 3 0^{\circ}

θ = - 18 0^{\circ} n + 3 0^{\circ}

x, 1 - 2 cos (x) = 0

0 = 1 + sin (θ)

2 cos (2 x) - cos (x) - 1 = 0

tan (x) \cdot tan (2 x) = 1

cos (x) cot (x) - 3 (1 - sin (x)) = 0

What is the general solution for tan(60-θ)= 1/(sqrt(3)) ?
The general solution for tan(60-θ)= 1/(sqrt(3)) is θ=-180n+30