What is the general solution for 0=4cos(3θ) ?

The general solution for 0=4cos(3θ) is θ= pi/6+(2pin)/3 ,θ= pi/2+(2pin)/3

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0=4cos(3θ)

0 = 4 cos (3 θ)

θ = \frac{π}{6} + \frac{2 πn}{3}, θ = \frac{π}{2} + \frac{2 πn}{3}

Solution steps

0 = 4 cos (3 θ)

Switch sides

4 cos (3 θ) = 0

Divide both sides by

4

cos (3 θ) = 0

General solutions for

cos (3 θ) = 0

3 θ = \frac{π}{2} + 2 πn, 3 θ = \frac{3 π}{2} + 2 πn

Solve

3 θ = \frac{π}{2} + 2 πn : θ = \frac{π}{6} + \frac{2 πn}{3}

Solve

3 θ = \frac{3 π}{2} + 2 πn : θ = \frac{π}{2} + \frac{2 πn}{3}

θ = \frac{π}{6} + \frac{2 πn}{3}, θ = \frac{π}{2} + \frac{2 πn}{3}

sin (θ) = \frac{3}{5}, sin (2 θ)

x, \frac{1}{6} = cos^{2} (x)

tan (x) + ∣ tan (x) ∣ = 1, - 2 π \leq, x \leq 2 π

2 sin^{2} (x) + 3 sin (x) = 1

11.33 = 1.59 cos (0.9 9^{\circ} (x - 18 2^{\circ})) + 12.14

What is the general solution for 0=4cos(3θ) ?
The general solution for 0=4cos(3θ) is θ= pi/6+(2pin)/3 ,θ= pi/2+(2pin)/3