What is the general solution for tan(x)+|tan(x)|=1,-2pi<= ,x<= 2pi ?

The general solution for tan(x)+|tan(x)|=1,-2pi<= ,x<= 2pi is No Solution for x\in\mathbb{R}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tan(x)+|tan(x)|=1,-2pi<= ,x<= 2pi

tan (x) + ∣ tan (x) ∣ = 1, - 2 π \leq, x \leq 2 π

No Solution for x \in R

Solution steps

tan (x) + ∣ tan (x) ∣ = 1, - 2 π, x \leq 2 π

Solve by substitution

tan (x) = \frac{1}{2}

tan (x) = \frac{1}{2}, - 2 π :

No Solution

Combine all the solutions

No Solution for x \in R

2 sin^{2} (x) + 3 sin (x) = 1

11.33 = 1.59 cos (0.9 9^{\circ} (x - 18 2^{\circ})) + 12.14

6 cos (3 x) = 6 cos (x)

4 cos (x) = - 22

tan (θ) = \frac{0.15}{0.5}

What is the general solution for tan(x)+|tan(x)|=1,-2pi<= ,x<= 2pi ?
The general solution for tan(x)+|tan(x)|=1,-2pi<= ,x<= 2pi is No Solution for x\in\mathbb{R}