What is the general solution for 10cos(x)=2.5sin(x) ?

The general solution for 10cos(x)=2.5sin(x) is x=1.32581…+pin

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10cos(x)=2.5sin(x)

10 cos (x) = 2.5 sin (x)

x = 1.32581 \dots + πn

Solution steps

10 cos (x) = 2.5 sin (x)

Rewrite using trig identities

2.5 tan (x) = 10

Multiply both sides by

10

25 tan (x) = 100

Divide both sides by

25

tan (x) = 4

Apply trig inverse properties

x = arctan (4) + πn

Show solutions in decimal form

x = 1.32581 \dots + πn

sin (0.6) - sin (0.6 + x) = 0.95

tan (x) = \frac{56}{91}

x, tan (x) = cot (x)

arccos (x) = \frac{5}{6}

5 cos (x) = - 2 sin^{2} (x) + 4, 0 \leq x \leq 2 π

What is the general solution for 10cos(x)=2.5sin(x) ?
The general solution for 10cos(x)=2.5sin(x) is x=1.32581…+pin