What is the general solution for arccos(x)= 5/6 ?

The general solution for arccos(x)= 5/6 is x=cos(5/6)

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arccos(x)= 5/6

arccos (x) = \frac{5}{6}

x = cos (\frac{5}{6})

Solution steps

arccos (x) = \frac{5}{6}

Apply trig inverse properties

x = cos (\frac{5}{6})

5 cos (x) = - 2 sin^{2} (x) + 4, 0 \leq x \leq 2 π

4^{\frac{1}{3}} sec (x) = 4 (\frac{1}{4 ^{\frac{1}{3}}}) csc (x)

\frac{1 + tan ^{2} ( x )}{1 + tan ^{2} ( x )} = 1 - sin^{2} (x)

θ, tan (θ) = \frac{2 3}{2}

\frac{- 3 + 4 cos ^{2} ( θ )}{1 - 2 sin ( θ )} = a + b sin (θ)

What is the general solution for arccos(x)= 5/6 ?
The general solution for arccos(x)= 5/6 is x=cos(5/6)