What is the general solution for sin(0.6)-sin(0.6+x)=0.95 ?

The general solution for sin(0.6)-sin(0.6+x)=0.95 is x=-0.39559…+2pin-0.6,x=pi+0.39559…+2pin-0.6

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sin(0.6)-sin(0.6+x)=0.95

sin (0.6) - sin (0.6 + x) = 0.95

x = - 0.39559 \dots + 2 πn - 0.6, x = π + 0.39559 \dots + 2 πn - 0.6

Solution steps

sin (0.6) - sin (0.6 + x) = 0.95

sin (0.6) = sin (\frac{3}{5})

sin (\frac{3}{5}) - sin (0.6 + x) = 0.95

Move

sin (\frac{3}{5})

to the right side

- sin (0.6 + x) = 0.95 - sin (\frac{3}{5})

Divide both sides by

- 1

sin (0.6 + x) = - 0.95 + sin (\frac{3}{5})

Apply trig inverse properties

0.6 + x = arcsin (- 0.95 + sin (\frac{3}{5})) + 2 πn, 0.6 + x = π + arcsin (0.95 - sin (\frac{3}{5})) + 2 πn

Solve

0.6 + x = arcsin (- 0.95 + sin (\frac{3}{5})) + 2 πn : x = arcsin (- 0.95 + sin (\frac{3}{5})) + 2 πn - 0.6

Solve

0.6 + x = π + arcsin (0.95 - sin (\frac{3}{5})) + 2 πn : x = π + arcsin (0.95 - sin (\frac{3}{5})) + 2 πn - 0.6

x = arcsin (- 0.95 + sin (\frac{3}{5})) + 2 πn - 0.6, x = π + arcsin (0.95 - sin (\frac{3}{5})) + 2 πn - 0.6

Show solutions in decimal form

x = - 0.39559 \dots + 2 πn - 0.6, x = π + 0.39559 \dots + 2 πn - 0.6

tan (x) = \frac{56}{91}

x, tan (x) = cot (x)

arccos (x) = \frac{5}{6}

5 cos (x) = - 2 sin^{2} (x) + 4, 0 \leq x \leq 2 π

4^{\frac{1}{3}} sec (x) = 4 (\frac{1}{4 ^{\frac{1}{3}}}) csc (x)

What is the general solution for sin(0.6)-sin(0.6+x)=0.95 ?
The general solution for sin(0.6)-sin(0.6+x)=0.95 is x=-0.39559…+2pin-0.6,x=pi+0.39559…+2pin-0.6