What is the general solution for tan(θ)=(-11/3-(-4/3))/(1+(-4/3)(-11/3)) ?

The general solution for tan(θ)=(-11/3-(-4/3))/(1+(-4/3)(-11/3)) is θ=-0.37724…+pin

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tan(θ)=(-11/3-(-4/3))/(1+(-4/3)(-11/3))

tan (θ) = \frac{- \frac{11}{3} - ( - \frac{4}{3} )}{1 + ( - \frac{4}{3} ) ( - \frac{11}{3} )}

θ = - 0.37724 \dots + πn

Solution steps

tan (θ) = \frac{- \frac{11}{3} - ( - \frac{4}{3} )}{1 + ( - \frac{4}{3} ) ( - \frac{11}{3} )}

Simplify

\frac{- \frac{11}{3} - ( - \frac{4}{3} )}{1 + ( - \frac{4}{3} ) ( - \frac{11}{3} )} : - \frac{21}{53}

Apply trig inverse properties

θ = arctan (- \frac{21}{53}) + πn

Show solutions in decimal form

θ = - 0.37724 \dots + πn

csc (2 x) = 2, x 0^{\circ} < x < 36 0^{\circ}

tan (x) = \frac{6}{7}

4 sin^{2} (x) + 2 cos (x) = 3

10 cos (x) = 2.5 sin (x)

sin (0.6) - sin (0.6 + x) = 0.95

What is the general solution for tan(θ)=(-11/3-(-4/3))/(1+(-4/3)(-11/3)) ?
The general solution for tan(θ)=(-11/3-(-4/3))/(1+(-4/3)(-11/3)) is θ=-0.37724…+pin