What is the general solution for sqrt(2)sin(3x)-1=0,0,2pi ?

The general solution for sqrt(2)sin(3x)-1=0,0,2pi is No Solution for x\in\mathbb{R}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sqrt(2)sin(3x)-1=0,0,2pi

2 sin (3 x) - 1 = 0, 0, 2 π

No Solution for x \in R

Solution steps

2 sin (3 x) - 1 = 0, 0, 2 π

Move

1

to the right side

2 sin (3 x) = 1

Divide both sides by

2

sin (3 x) = \frac{2}{2}

General solutions for

sin (3 x) = \frac{2}{2}

3 x = \frac{π}{4} + 2 πn, 3 x = \frac{3 π}{4} + 2 πn

Solve

3 x = \frac{π}{4} + 2 πn : x = \frac{π}{12} + \frac{2 πn}{3}

Solve

3 x = \frac{3 π}{4} + 2 πn : x = \frac{π}{4} + \frac{2 πn}{3}

x = \frac{π}{12} + \frac{2 πn}{3}, x = \frac{π}{4} + \frac{2 πn}{3}

Solutions for the range

0

No Solution for x \in R

4 cos^{2} (x) = 2 cos (x) + 1

\frac{13}{sin ( 10 8 ^{\circ} )} = \frac{9}{sin ( x )}

tan^{2} (x) + 5 cos (x) - 8 = 0

3 sin (x) = 2 - 2 sin^{2} (x)

100 = 100 + 40 sin (\frac{9 π}{4} t)

What is the general solution for sqrt(2)sin(3x)-1=0,0,2pi ?
The general solution for sqrt(2)sin(3x)-1=0,0,2pi is No Solution for x\in\mathbb{R}