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Popular >

6cos(7θ)=0

Solution

6 cos (7 θ) = 0

Solution

θ = \frac{π}{14} + \frac{2 πn}{7}, θ = \frac{3 π}{14} + \frac{2 πn}{7}

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Solution steps

6 cos (7 θ) = 0

Divide both sides by

6

cos (7 θ) = 0

General solutions for

cos (7 θ) = 0

7 θ = \frac{π}{2} + 2 πn, 7 θ = \frac{3 π}{2} + 2 πn

Solve

7 θ = \frac{π}{2} + 2 πn : θ = \frac{π}{14} + \frac{2 πn}{7}

Solve

7 θ = \frac{3 π}{2} + 2 πn : θ = \frac{3 π}{14} + \frac{2 πn}{7}

θ = \frac{π}{14} + \frac{2 πn}{7}, θ = \frac{3 π}{14} + \frac{2 πn}{7}

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Frequently Asked Questions (FAQ)

What is the general solution for 6cos(7θ)=0 ?
The general solution for 6cos(7θ)=0 is θ= pi/(14)+(2pin)/7 ,θ=(3pi}{14}+\frac{2pin)/7