What is the general solution for 1/2 cos(2x-pi/3)+4=0 ?

The general solution for 1/2 cos(2x-pi/3)+4=0 is No Solution for x\in\mathbb{R}

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1/2 cos(2x-pi/3)+4=0

\frac{1}{2} cos (2 x - \frac{π}{3}) + 4 = 0

No Solution for x \in R

Solution steps

\frac{1}{2} cos (2 x - \frac{π}{3}) + 4 = 0

Move

4

to the right side

\frac{1}{2} cos (2 x - \frac{π}{3}) = - 4

Multiply both sides by

2

cos (2 x - \frac{π}{3}) = - 8

- 1 \leq cos (x) \leq 1

No Solution for x \in R

sin (B) = \frac{16 sin ( 10 4 ^{\circ} )}{25}

sin (t) = \frac{3}{5}, cos (t) = \frac{4}{5}

cos (3 x) = 4 cos^{2} (x) - 3 cos (x)

2 sin (2 θ) = 0

- sin (2 x) = - 2 sin (x)

What is the general solution for 1/2 cos(2x-pi/3)+4=0 ?
The general solution for 1/2 cos(2x-pi/3)+4=0 is No Solution for x\in\mathbb{R}