What is the general solution for 3cos^2(x)+6cos(x)=-3,0<= x<= 2pi ?

The general solution for 3cos^2(x)+6cos(x)=-3,0<= x<= 2pi is x=pi

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3cos^2(x)+6cos(x)=-3,0<= x<= 2pi

3 cos^{2} (x) + 6 cos (x) = - 3, 0 \leq x \leq 2 π

x = π

Solution steps

3 cos^{2} (x) + 6 cos (x) = - 3, 0 \leq x \leq 2 π

Solve by substitution

cos (x) = - 1

cos (x) = - 1, 0 \leq x \leq 2 π : x = π

Combine all the solutions

x = π

tan (θ) = 7, sec^{2} (θ)

4 cos (x - 4 5^{\circ}) + 7 = 10, 0^{\circ} \leq x \leq 36 0^{\circ}

6 cosh^{2} (x) + 4 sinh (x) = 7

53 tan (x) + 3 = 83 tan (x)

cos^{2} (x) = - 0.5

What is the general solution for 3cos^2(x)+6cos(x)=-3,0<= x<= 2pi ?
The general solution for 3cos^2(x)+6cos(x)=-3,0<= x<= 2pi is x=pi