What is the general solution for cos(x)=-0.397 ?

The general solution for cos(x)=-0.397 is x=1.97904…+2pin,x=-1.97904…+2pin

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cos(x)=-0.397

cos (x) = - 0.397

x = 1.97904 \dots + 2 πn, x = - 1.97904 \dots + 2 πn

Solution steps

cos (x) = - 0.397

Apply trig inverse properties

x = arccos (- 0.397) + 2 πn, x = - arccos (- 0.397) + 2 πn

Show solutions in decimal form

x = 1.97904 \dots + 2 πn, x = - 1.97904 \dots + 2 πn

sin (2 x) cos (x) + cos (2 x) sin (x) = \frac{3}{2}

cos (x) = \frac{5 2}{10}

4 tan (x) + 4 = 0

4 sin (θ) - 3 = 0, 0 \leq θ \leq 2 π

x, 0 = - 5 sin (2 x)

What is the general solution for cos(x)=-0.397 ?
The general solution for cos(x)=-0.397 is x=1.97904…+2pin,x=-1.97904…+2pin