What is the general solution for 4sin(θ)-3=0,0<= θ<= 2pi ?

The general solution for 4sin(θ)-3=0,0<= θ<= 2pi is θ=0.84806…,θ=pi-0.84806…

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4sin(θ)-3=0,0<= θ<= 2pi

4 sin (θ) - 3 = 0, 0 \leq θ \leq 2 π

θ = 0.84806 \dots, θ = π - 0.84806 \dots

Solution steps

4 sin (θ) - 3 = 0, 0 \leq θ \leq 2 π

Move

3

to the right side

4 sin (θ) = 3

Divide both sides by

4

sin (θ) = \frac{3}{4}

Apply trig inverse properties

θ = arcsin (\frac{3}{4}) + 2 πn, θ = π - arcsin (\frac{3}{4}) + 2 πn

Solutions for the range

0 \leq θ \leq 2 π

θ = arcsin (\frac{3}{4}), θ = π - arcsin (\frac{3}{4})

Show solutions in decimal form

θ = 0.84806 \dots, θ = π - 0.84806 \dots

x, 0 = - 5 sin (2 x)

1.2 sin (2 4^{\circ}) = 1.2 sin (x)

cos (C) = 20.09 - \frac{27.1441}{19.6}

3 sin (x) - cos^{2} (x) = - 3

csc (4 x) = 0

What is the general solution for 4sin(θ)-3=0,0<= θ<= 2pi ?
The general solution for 4sin(θ)-3=0,0<= θ<= 2pi is θ=0.84806…,θ=pi-0.84806…