What is the general solution for solvefor x,0=-5sin(2x) ?

The general solution for solvefor x,0=-5sin(2x) is x=pin,x= pi/2+pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solvefor x,0=-5sin(2x)

solve for

x, 0 = - 5 sin (2 x)

x = πn, x = \frac{π}{2} + πn

Solution steps

0 = - 5 sin (2 x)

Switch sides

- 5 sin (2 x) = 0

Divide both sides by

- 5

sin (2 x) = 0

General solutions for

sin (2 x) = 0

2 x = 0 + 2 πn, 2 x = π + 2 πn

Solve

2 x = 0 + 2 πn : x = πn

Solve

2 x = π + 2 πn : x = \frac{π}{2} + πn

x = πn, x = \frac{π}{2} + πn

1.2 sin (2 4^{\circ}) = 1.2 sin (x)

cos (C) = 20.09 - \frac{27.1441}{19.6}

3 sin (x) - cos^{2} (x) = - 3

csc (4 x) = 0

2 sin (2 x) = - cos (2 x)

What is the general solution for solvefor x,0=-5sin(2x) ?
The general solution for solvefor x,0=-5sin(2x) is x=pin,x= pi/2+pin